weight of Fe(NH4)2(SO4)2*6H2O= 0.1761 g concentration of stock solution of Fe(II)= ? Weigh (to the nearest 0.2 mg) 0.17x

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answerhappygod
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weight of Fe(NH4)2(SO4)2*6H2O= 0.1761 g concentration of stock solution of Fe(II)= ? Weigh (to the nearest 0.2 mg) 0.17x

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weight of Fe(NH4)2(SO4)2*6H2O= 0.1761 g
concentration of stock solution of Fe(II)= ?
Weigh (to the nearest 0.2 mg) 0.17xx g of reagent-grade
Fe(NH4)2(SO4)2 • 6H2O into a 250 mL volumetric flask. Dissolve in
50 mL of distilled water containing 1 to 2 mL of concentrated
sulfuric acid; Dilute to the mark, and mix well.
Transfer 25.00 mL of the prepared solution to a 250 mL volumetric
flask. Dilute with distilled water to the mark, and mix well.
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