- Find the total impedance Z in the circuit given below: 2=3√1 2- 3+ ju 30 Зно of 22.4L 36.86 ?- For the circuit below,

[answerhappygod]

1 (74 KiB) Viewed 55 times

2 (68.43 KiB) Viewed 55 times

- Find the total impedance Z in the circuit given below: 2=3√1 2- 3+ ju 30 Зно of 22.4L 36.86 ?- For the circuit below, determine the value for the currents 12 and 13 jn n Is 12= 12230 1₂ 260 12/30° V 20 +60° V I3 = 12230-620 1290 = 7.43/-76.20 3- For the circuit given below, determine the voltage across the 2 Ohm resistor. 252 0.01F 0.05 H m + 60 cos(504+20) (2) Ⓒ100 cos 50€ V 01H 552 0.005F For the circuit below, us = 60 sin (2000t+100°) V, and the voltage source is connected in series with a source resistance Rs = 14022 which is connected to an RL load with R=30002 and L=6 mH, calculate the average power supplied by the voltage source R₂ a 3R For the circuit below, calculate the average power dissipated in the capacitor and the total current, I. Then, if the frequency is 60Hz, determine the inductance L V=10/20¹2-20 ₁-0 =₁=-₁¹0Z₂=40 CS Scanned with CamScanner لسنا and meaningful analysis to receive at least partial credit. Element Phasor Eq. Impedance R Z = R V = RI V = jwLl Z = jwL L 1 1 C V = -1 Z = jwC jwC 212210 5153 Average Power P=-=-Vμ³μ cos(0₁-0₂) M ١٩٧ لي + 12 ،1 ، 2 19941 =66304

6- For the circuit in the figure below, find Z, for maximum average power transfer. (2 points) Then compute the maximum average power supplied to the load. 24/0°V 12/0 V Voc -jan Zipt = ZTH Pmax 20 j20 ZL 2 4RTH 7- For the circuit in the figure below, if a load impedance to be connected between points a and b, determine the value of Z, for maximum average power transfer. j20 2 m 10 Ω www o a 50/30° --/10 2 -ob 8- For the circuit in the figure below, if a load impedance to be connected between points a and b, determine the maximum average power that can be transferred to the load. -00 ΒΩ; 5/45° A 102 -j60 -ob 9- For the ideal transformer circuit given below, calculate 1₁. -jan ₁20 20- 1:2 Www 36/0V( 12/0° V An automotive alternator is rated 550 VA and 20 V. It delivers its rated voltamperes at a power factor of 0.90. The resistance per phase is 0.05 £2, and the field takes 2 A at 12 V. If the friction and windage loss is 35 W and the core loss is 40 W, calculate the percent efficiency under rated conditions. (8 points) Have a**) ...*..*) G. Wonderful Day ==