full-l 20. Repeat the solution of Prob. 19 for a power factor of 0.8 leading. 21. A three-phase 1,000-kva 2,300-volt alt

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answerhappygod
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full-l 20. Repeat the solution of Prob. 19 for a power factor of 0.8 leading. 21. A three-phase 1,000-kva 2,300-volt alt

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Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 1
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 1 (25 KiB) Viewed 24 times
no.20
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 2
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 2 (23.21 KiB) Viewed 24 times
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 3
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 3 (30.07 KiB) Viewed 24 times
no.18 also reference
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 4
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 4 (157.96 KiB) Viewed 24 times
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 5
Full L 20 Repeat The Solution Of Prob 19 For A Power Factor Of 0 8 Leading 21 A Three Phase 1 000 Kva 2 300 Volt Alt 5 (20.6 KiB) Viewed 24 times
no.2 only change the question.... thank you
full-l 20. Repeat the solution of Prob. 19 for a power factor of 0.8 leading. 21. A three-phase 1,000-kva 2,300-volt alternator is short-circuited and is operated at rated speed to produce rated current. With the short circuit removed and the 1.200 The effective
Xs. The d-c resistance between 19. Calculate the per cent regulation for Prob. 18 when the alternator delivers its full-load kilovolt-amperes at a power factor of 0.6 lagging. 20 Repeat the solution of Prob. 19 for a power factor of 0.8 leading.
cent regulation. 18. Assuming that the curves of Fig. 166 are for a 400-kva 2,200-volt three-phase alter- nator, calculate the synchronous impedance Zs and the synchronous reactance Xs. The d-c resistance between terminals is 0.9 ohm. 10 Calculate the per cent regulation for Prob. 18 when the alternator delivers its
full-load line current. 14. If the alternator of Prob. 13 delivers a load of 3,600 kw at a power factor of 0.82, calculate the line current. 15. The voltage of an alternator rises from 460 volts at full load to 535 volts at no load. Calculate the per cent regulation. 16. A three-phase Y-connected alternator delivers a unity power-factor load at 230 volts. If the synchronous-reactance voltage drop is 60 volts per phase, calculate the per cent regulation, neglecting the resistance voltage drop. 17. If the resistance voltage drop per phase in Prob. 16 is 5 volte, calculate the per cent regulation. 18. Assuming that the curves of Fig. 166 are for a 400-kva 2,200-volt three-phase alter- nator, calculate the synchronous impedance Za and the synchronous reactance Xs. The d-c resistance between terminals is 0.9 ohm. 19. Calculate the per cent regulation for Prob. 18 when the alternator delivers its full-load kilovolt-amperes at a power factor of 0.6 lagging. 20. Repeat the solution of Prob. 19 for a power factor of 0.8 leading. 21. A three-phase 1,000-kva 2,300-volt alternator is short-circuited and is operated at rated speed to produce rated current. With the short circuit removed and the same excitation, the voltage between stator terminals is 1,300. The effective (corrected) resistance between stator terminals is 2 ohms. Determine the per cent regulation of the alternator at a power factor of 0.8 lagging. 22. Repeat Prob. 21 for a power factor of 0.8 leading. 23. A 1,000-kva 4,600-volt three-phase alternator ie short-circuited, and, operating
A. 2. The name-plate speed of a 25-cycle induction motor is 720 rpm. If the speed at no load is 745 rpm, calculate: (a) the alip; (b) the per cent regulation.
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