+18V 2.2ΚΩ IDss=8mA VGS(off) -8V 0.39ΚΩ - 4V

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answerhappygod
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+18V 2.2ΚΩ IDss=8mA VGS(off) -8V 0.39ΚΩ - 4V

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Given the circuit below, please help me find the following:
A. Input loop equation
B. Drain current( ID)
C. Gate-source voltage (VGS)
D. Drain-source voltage( VDS)
E. Potential at the source terminal( VS)
Please show complete and detailed solution. Thank you! Will give
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+18V 2.2ΚΩ IDss=8mA VGS(off) -8V 0.39ΚΩ - 4V
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