Directions 1. Place equal masses of 150 - 200 grams on each side of the apparatus. 2. Continue to add a small amount of

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Directions 1. Place equal masses of 150 - 200 grams on each side of the apparatus. 2. Continue to add a small amount of

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Directions 1 Place Equal Masses Of 150 200 Grams On Each Side Of The Apparatus 2 Continue To Add A Small Amount Of 1
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Directions 1. Place equal masses of 150 - 200 grams on each side of the apparatus. 2. Continue to add a small amount of mass to one side of the apparatus, until this side moves down, at a constant speed, when tapped. This is the mass to overcome friction in the pulley. 3. With the frictional mass still on, add an additional 10 grams to the descending side and time the fall for a predetermined distance traveled. 4. Transfer five additional grams for test number two, and ten additional grams for test number three and time the fall. 5. Calculate the acceleration using motion equations for each trial. 6. Calculate the net force and acceleration using Newton's 2nd law for each trial. 7. Find the percent difference between both methods.
The mass found to overcome friction 4.00 g Distance 139 cm Both sides of the Atwood Machine start with 200.00 g then 4.00 g were added to one side to overcome friction. Then additional mass was added to make the system accelerate. The photos below show the setup. Trial 1 time when 10 g added. Trial 2 time when 15g total were added. Then trial 3 when 25 g total were added. To the frictional mass.
1000359 000 ON/RESET FLINN SCIENTIFIC, INC START/STOP 100286 LAP ON/RESET FLINN SCIENTIFIC, INC START/STOP
0:0002 15 FLINN SCIENTIFIC, INC LAP ON/RESET START/STOP
Atwood Machine Results (kg) 1. Mass to Overcome Friction_ 2. Frictional Force 3. Using Motion Equations Average Time (s) Distance (m) Acceleration (m/s) 4. Using Newton's 2nd Law Small Mass (kg) Large Mass (kg) Net Force (N) Acceleration (m/s²) 5. Calculate the % Difference %Difference Trial 1 (N) Trial 2 Trial 3
Sample Atwood Catulations Intram MASS to overcome Frict. 3.00g Forces of flection Fring: 300g (ny) (9.81m) - 0.0294 ) ik Aug tome - 2.165 2.125 2.20, 215 + 3 Note I gave you Ang times. Distances 0.50m acad 2 (0.560m).0.240m (2.165) st MEASUD Starting out m = m2 200 g or 0.200kg Small mass aoog - 0.200 kg Lange MASS - 200g+ 3.00g + wog= 213 or 0.213 kg : MARS Abp to O smail faut Fret mig-mag-meg-(m, M2-M.) (0.213 Kg - 0.200ly -0.005x) 4.813.) - 0.0981~ - Note: equal 10g that's what makes the system accelert = -0.28m 3 a= Furt 0.0981. mume 0.21319 +0.2006 % D.fference = \Exp, EXT] X100 O % Diff - (0.240 -0.236) Torayon +0.23894 ) X 100- 0.837%
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