I'm just looking to understand the steps to workout this
integral, specifically why does the r term disappear?
In the case of a point charge q at the origin, the flux of E through a spherical surface of radius r is 1 $ E da = = S 426 () 12 = • (r2 sin & de dof) = = = 1 -9. EO (2.12) 4πέο
I'm just looking to understand the steps to workout this integral, specifically why does the r term disappear?
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answerhappygod
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I'm just looking to understand the steps to workout this integral, specifically why does the r term disappear?
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