Researchers studied the effect that varying levels of two drugs, Brand Rand Brand A had on a child's ability to follow n

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Researchers studied the effect that varying levels of two drugs, Brand Rand Brand A had on a child's ability to follow n

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Researchers Studied The Effect That Varying Levels Of Two Drugs Brand Rand Brand A Had On A Child S Ability To Follow N 1
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Researchers studied the effect that varying levels of two drugs, Brand Rand Brand A had on a child's ability to follow nules when the child diagnosed with attention deficit hyperactivity disorder (ADHD) They randomly assigned children to one of five treatment groups: placebo, 10 mg Brand R. 175 mg of Brand R, 7.5 mg of Brand A, or 12 5 mg of Brand A twice a day. They recorded a score that indicated the child ability to follow rules, with a higher score indicating a higher ability to follow rules. The accomparrying data are based on their study. Complete parts a) through g) below. Click the icon to view the data table GUIDE a) the data was collected using a completely randomized design. Explain what this means OA. Each child was randomly assigned to a treatment. O B. Each drug treatment was randornly assigned to a child. OC. Each score on ability to follow rules was randomly assigned to a child OD. Each child was randomly selected from the population b) What is the response variable in this study? What explanatory vanable was controlled and fixed at five levels? The response variable is W was controlled and fixed at five levels c) The children were randomly assigned to one of five treatment groups. What role does randomization play in this study? O A. Randomization helps to prevent response bias B. Randomization helps to control the values of any lurking variables, OC. Randomization helps to even out the effect of any lurking variables that were not controlled in the study OD. Randomization is only needed to preserve the privacy of the children The

d) What are the null and alternative hypotheses in this study? Ho H a) Test the null hypothesis that the mean score for each treatment is the same at the a= 0.05 level of significance Note that the requirements for a one-way ANOVA are satisfied The test statistic is = 0 (Round to two decimal places as needed) The P-value is I (Round to three decimal places as needed) Choose the correct conclusion below. the null hypothesis. There sufficient evidence at the or= 0.05 level of significance to conclude that of the null hypothesis is rejected in parte), use Tukey's test to determine which pairwise means differ using a familymse error rate of a = 005 Choose the correct conclusion below. OA HP PRO PRIZS HA75 HA12S OB. HP WRLO HRITS HATS HA125 OCUP HRO HR175 WAT5 HA125 ODHP PRO HR17.5 PALS. HA125 O E The null hypothesis was not rejected

9) Draw boxplots of the five treatment levels to support the analytic results obtained in parts a) and b) Choose the correct anawer below Ос. СА В. sign 1125 A75 A12.5 A75 175 R10 d AS A125 AYS R175 R10 o 9 R175 R10 P P (SP22 SIP 150 60 150 60

Data table Placebo 10 mg 47 19 34 59 28 70 23 Brand R Brand R Brand A Brand A 17.5 mg 7.5 mg 12.5 mg 99 37 58 83 76 84 72 115 59 76 83 81 44 44 92 85 88 74 72 71 64 51 91 59 100 70 63 90
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