If X is a continuous RV with PDF given by: x < 0 f(x) = 0SX S2 3 x > 2 0 i. ii. 1 Find Fx) and draw it. *< 0: F(x) = f (

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answerhappygod
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If X is a continuous RV with PDF given by: x < 0 f(x) = 0SX S2 3 x > 2 0 i. ii. 1 Find Fx) and draw it. *< 0: F(x) = f (

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If X Is A Continuous Rv With Pdf Given By X 0 F X 0sx S2 3 X 2 0 I Ii 1 Find Fx And Draw It 0 F X F 1
If X Is A Continuous Rv With Pdf Given By X 0 F X 0sx S2 3 X 2 0 I Ii 1 Find Fx And Draw It 0 F X F 1 (145.2 KiB) Viewed 25 times
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If X is a continuous RV with PDF given by: x < 0 f(x) = 0SX S2 3 x > 2 0 i. ii. 1 Find Fx) and draw it. *< 0: F(x) = f (t)dt = f* Odt = 0 osxs 2: F(x) = S(t)dt = $of(t)dt + Sc*/(t)dt L'ode + Stdt = 0 + (L.) - x > 2:F(x) = -f(t)dt = f(t)dt + Si f(t)dt + $(t)dt Lode + Smedt + ["ode = 0 + (4 lk) + 0 = = 1 Odt + = F(x) OSE + = 0 4 + 0 = 4 2 0 F(x) = x < 0 OsX2 x > 2 0 Does integration always start with negative infinity? And the x in the integral confuses me so I can't solve well Can I replace x with an existing value such as 1<x<2 Please explain the answer If you use handwriting please make it clear
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