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answerhappygod
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Please show work
Please show work
3. A regional jet that can seat 36 passengers has a weight capacity of 7500 pounds. Suppose that the passen- gers that use this plane come from a population with a mean weight of 200 pounds and a standard deviation of 40 pounds. (Assume that this weight includes any baggage they may bring on board the plane.) The approximate probability that the weight of 36 randomly selected passengers from this population boarding the plane will exceed the weight capacity of the regional jet is (a) 1-0 7500-(36) (200) 36(402) (b) Φ 7500-(36) (200) 36(402) (c) 1-0 7500-(36) (200) 36(40) 7500-(36) (200) /36(40) (e) 1-0 7500-(36) (200) (36) (40) (d) • 4. For the geometric distribution with probability mass function (pmf) f(x;0) = 0(1 - 0)", x = 0,1,2,..., 0 < 0 <1, = 1 For this distribution, the maximum likelihood estimator is Ô = n) (n + XI-1X;). The test statistic used in the generalized likelihood ratio test is given by (a) 2 log LR = 2 [2=log() + (n – 2+1 1;) log (1-6)] (b) 2 log LR = 2 L?-1 ; log (%) + n log (16)] (c) 2 log LR = 2 log [(ôr (1 – Ô) 2?_, X;) *:)] (d) 2 log LR 2 log [f* (n log(@) + L+1 ti log(1 – 0))] (e) 2log LR = 2 [n log () + -1 log (1)] d02 = +in =
3. A regional jet that can seat 36 passengers has a weight capacity of 7500 pounds. Suppose that the passen- gers that use this plane come from a population with a mean weight of 200 pounds and a standard deviation of 40 pounds. (Assume that this weight includes any baggage they may bring on board the plane.) The approximate probability that the weight of 36 randomly selected passengers from this population boarding the plane will exceed the weight capacity of the regional jet is (a) 1-0 7500-(36) (200) 36(402) (b) Φ 7500-(36) (200) 36(402) (c) 1-0 7500-(36) (200) 36(40) 7500-(36) (200) /36(40) (e) 1-0 7500-(36) (200) (36) (40) (d) • 4. For the geometric distribution with probability mass function (pmf) f(x;0) = 0(1 - 0)", x = 0,1,2,..., 0 < 0 <1, = 1 For this distribution, the maximum likelihood estimator is Ô = n) (n + XI-1X;). The test statistic used in the generalized likelihood ratio test is given by (a) 2 log LR = 2 [2=log() + (n – 2+1 1;) log (1-6)] (b) 2 log LR = 2 L?-1 ; log (%) + n log (16)] (c) 2 log LR = 2 log [(ôr (1 – Ô) 2?_, X;) *:)] (d) 2 log LR 2 log [f* (n log(@) + L+1 ti log(1 – 0))] (e) 2log LR = 2 [n log () + -1 log (1)] d02 = +in =
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