Let f(x) = 3Vx + 5. If h = 0, then the difference quotient can be simplified as = f(x + h) – f(x) h A Bx + Ch+ +VT > х w
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Let f(x) = 3Vx + 5. If h = 0, then the difference quotient can be simplified as = f(x + h) – f(x) h A Bx + Ch+ +VT > х w
Let f(x) = 3Vx + 5. If h = 0, then the difference quotient can be simplified as = f(x + h) – f(x) h A Bx + Ch+ +VT > х where A, B, and C are constants. (Note: It's possible for one or more of these constants to be 0.) Find the constants. A = = B = and C= f(x + h) – f(x) Use your answer from above to find f'(x) = lim h h→0 Finally, find each of the following: f'(1) = = , f'(2) = = , and f(3) = CE G
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