According to Hooke's Law, the force required to maintain a spring stretched x units beyond its natural length is proport

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answerhappygod
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According to Hooke's Law, the force required to maintain a spring stretched x units beyond its natural length is proport

Post by answerhappygod »

According to Hooke's Law, the force required to maintain a
spring stretched x units beyond its natural
length is proportional to x. This means
that f(x) = kx, for some
constant k.
Since our spring is stretched 3 in., which is equal
to ft, we have 13 =
k. So k = lb/ft.
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