"Doc 1.4 1.5 2.1 25 y RADOX (3,14) 1b)--x2+6+x+5 0.5 | 12(x)=x² +5 -5 Sally is interested in finding the area between fi

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Doc 1 4 1 5 2 1 25 Y Radox 3 14 1b X2 6 X 5 0 5 12 X X 5 5 Sally Is Interested In Finding The Area Between Fi 1 (37 KiB) Viewed 25 times

"Doc 1.4 1.5 2.1 25 y RADOX (3,14) 1b)--x2+6+x+5 0.5 | 12(x)=x² +5 -5 Sally is interested in finding the area between fix) = - x^2 + 6x + 5 and g(x) = x^2 + 5, as bounded at the points of intersection where x = 0 and x = 3. The desired area is the shaded region in the given graph Sally decides to set up an integral in the form f(f(x) - 3(x))dx, which she will then evaluate between x = 0 and x = 3. Is this a good set-up? Yes: S(x) - 3(x)dx properly represents the desired region. No; Sally should reverse the functions and express the integral as f($(x) = f(x)\dx.