Consider the 2nd order curve -10.42 +6° 7-10.73 +8.6 – 10.7+7=0 Calculate a positive angle V= such that after the change

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Consider The 2nd Order Curve 10 42 6 7 10 73 8 6 10 7 7 0 Calculate A Positive Angle V Such That After The Change 1 (17.41 KiB) Viewed 23 times

Consider the 2nd order curve -10.42 +6° 7-10.73 +8.6 – 10.7+7=0 Calculate a positive angle V= such that after the change of coordinates (rotation) cos(v) sin() - sin(o) cos(p) 0) - ). the equation for the curve is $1172 + 12.72 + 5* +Egy+7=0 Let us assume that i < 12. Then calculate du = Az = = 5 = = = ية After performing the shift z = + 51 y=3 +52 the equation for the 2nd order curve takes its canonical form 111*2 + 12.7 +2=0 Calculate $1 = S2 = and c=