- 8 Integrate S 4x2 16 X2 Dx Using The Following Rule Su Va U Du A U 2u2 A Va Uz A Arcsin C 1 (14.92 KiB) Viewed 36 times
8. Integrate S 4x2 /(16 - x2) dx using the following rule: - Su Va? – u_ du = a (u(2u2 – a?)Va? – uż + a* arcsin + C. ]
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8. Integrate S 4x2 /(16 - x2) dx using the following rule: - Su Va? – u_ du = a (u(2u2 – a?)Va? – uż + a* arcsin + C. ]
8. Integrate S 4x2 /(16 - x2) dx using the following rule: - Su Va? – u_ du = a (u(2u2 – a?)Va? – uż + a* arcsin + C. ] - = - +
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