- Let P Be The Tangent Plane To The Graph Of G X Y 16 8x2 16y2 At The Point 4 2 176 Let F X Y 16 X2 1 (152.53 KiB) Viewed 26 times
= Let P be the tangent plane to the graph of g(x, y) = 16 – 8x2 – 16y2 at the point (4,2, –176). Let f(x, y) = 16 – x2 -
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= Let P be the tangent plane to the graph of g(x, y) = 16 – 8x2 – 16y2 at the point (4,2, –176). Let f(x, y) = 16 – x2 -
= Let P be the tangent plane to the graph of g(x, y) = 16 – 8x2 – 16y2 at the point (4,2, –176). Let f(x, y) = 16 – x2 - y2. Find the point on the graph of f where the tangent plane is parallel to P. (Use symbolic notation and fractions where needed. Give your answer in the form (*,*,*)). point:
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