f(x)= ln((x-3)(2x+4)^3 / (x^2+1)^2)
1) +(x) = { x + 2 + sin "(x) + e 2x + e ' - + TT е
f(x)= ln((x-3)(2x+4)^3 / (x^2+1)^2)
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f(x)= ln((x-3)(2x+4)^3 / (x^2+1)^2)
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