During a program meant to recover a depleted wolf population, the population of wolves increases so that the number of w

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During A Program Meant To Recover A Depleted Wolf Population The Population Of Wolves Increases So That The Number Of W 1 (16 KiB) Viewed 26 times

During A Program Meant To Recover A Depleted Wolf Population The Population Of Wolves Increases So That The Number Of W 2 (25.13 KiB) Viewed 26 times

During a program meant to recover a depleted wolf population, the population of wolves increases so that the number of wolves years from the present is given by the function wit) - 125(1.1---) (a) Sketch the graph of Wt) fort 20. Note any asymptotes and intercepts. WID Wit 101 lan 120 100 80 60 40 20 20 40 60 80 100 120 140 B 10

asymptotes: intercepts y 137 y 12 X X (b) What is the population of wolves initially? 12 xwolves (c) Find the inverse function. (Use W for WD)) -I(0.6) X How long does it take for the population to reach 100 wolves? (Round your answer to one decimal place) 0.5 хуг (d) What interpretation does the asymptotic line serve for the wolf population? In the long run the population approaches 138 X wolves. Recall that it is a one-to-one function with domain A and range B, then / has an inverse function, 1-Agiven by exity. Find the demand range of the given function w(t). Reflect, translate, and stretch the graph of e' by the given values to obtain the graph of wit). What happens to the quantity when becomes very large and positive? How does this explain the location of the horizontal asymptote? Use the expression for W) to solve for in terms of that? given in years. What value of t corresponds to the initial population of wolves? How can the inverse function be used to find the bre needed for the population to reach