The point P(4, 7) lies on the curve y = VT + 5. If Q is the point (X, VT + 5), find the slope of the secant line PQ for

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answerhappygod
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The point P(4, 7) lies on the curve y = VT + 5. If Q is the point (X, VT + 5), find the slope of the secant line PQ for

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The Point P 4 7 Lies On The Curve Y Vt 5 If Q Is The Point X Vt 5 Find The Slope Of The Secant Line Pq For 1
The Point P 4 7 Lies On The Curve Y Vt 5 If Q Is The Point X Vt 5 Find The Slope Of The Secant Line Pq For 1 (25.72 KiB) Viewed 31 times
The point P(4, 7) lies on the curve y = VT + 5. If Q is the point (X, VT + 5), find the slope of the secant line PQ for the following values of z. If x = 4.1, the slope of PQ is: and if x = 4.01, the slope of PQ is: and if x = 3.9, the slope of PQ is: and if x = 3.99, the slope of PQ is: = Based on the above results, guess the slope of the tangent line to the curve at P(4, 7).

= Let f(x) = 7.6x2 – 7.9x. Find the equation of the secant line on the graph of f(c) between 3 and 22 = 11. Write your answer in mx + b format. 21 = y =

= Approximate the area between the x-axis and the graph of f(x) = v= +1 over the interval [2, 4] by calculating the sum of the areas of 4 rectangles with equal widths along the interval. The rectangles should be placed on the z-axis and the heights should be the function values at the left endpoint of each subinterval, as shown below. covo 5 4 4 2 Round to three decimal places. Area
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