Part 1. Using the substitution: u = x8. Re-write the indefinite integral then evaluate in terms of u. x" cos (28) dx 47 = Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have | ?cos (zº) dx = z =O Note: answer should be in terms of x only
Part 1. - Using the substitution: u = 26 – 1. Re-write the indefinite integral then evaluate in terms of u. | 52*(z® – 1)*dx = 5 0-0 Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have 8 | 528 (zº – 1)* dx = = Note: answer should be in terms of x only
Part 1. Using the substitution: u = x8. Re-write the indefinite integral then evaluate in terms of u. x" cos (28) dx 47
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Part 1. Using the substitution: u = x8. Re-write the indefinite integral then evaluate in terms of u. x" cos (28) dx 47
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