Find The Solution X T Of The Differential Equation X 3x 2x 0 X 0 A X 0 B L X X S L X Sx S X 0 1 (555.91 KiB) Viewed 27 times
Please resolve this and please show all steps, if any
mistakes.
Find x(t)
Find the solution x(t) of the differential equation x"+3x'+2x = 0 x(0) = a x'(0) = b = = L(x) = X(s) L(x') = sX(s) – x(0) L(x") = s’X($) - sx(0) – x'(0) (sX(s) – sX(s) – x'(0))+ 3(sX(s) – x(0))+2(X«s)) = 0 s’X(s) – sx(0) – b +35X(s) – 3a + 2X($) = 0) (s? +3s + 2)x (s) = as +b+3a as + b + 3a X(S) = [s: ) + 3s + 2) as + b + 3a 2a +b a + b (s+1)(s +2) 5+1 S +2 2a +b a + b X(S) = S+1 S +2 2a +b a + b L'(X(s)) = ['( +1 X(t) = (2a+b)e" - (a+b)e-21 us.bbcollab.com is sharing your screen ****2) S +2 =
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!