The Aerodynamic Drag On A Car Depends On The Shape Of The Car For Example The Car Shown In The Figure Below Has A Dr 1 (21.99 KiB) Viewed 33 times
The Aerodynamic Drag On A Car Depends On The Shape Of The Car For Example The Car Shown In The Figure Below Has A Dr 2 (19.42 KiB) Viewed 33 times
The Aerodynamic Drag On A Car Depends On The Shape Of The Car For Example The Car Shown In The Figure Below Has A Dr 3 (17.65 KiB) Viewed 33 times
The aerodynamic drag on a car depends on the "shape" of the car. For example, the car shown in the figure below has a drag coefficient Coe of 0.33 with the windows and roof closed. With the windows and roof open, the drag coefficient increases to Co. -0.46. With the windows and roof open, at what speed is the amount of power needed to overcome aerodynamic drag the same as it is at 65 mph with the windows and roof closed? Assume the frontal area remains the same. Recall that power is force times velocity. Windows open, roof open Windows and roof closed Co=C₁x Co-Co The drag coefficient is defined as Co- PUA
(a) What is the expression for the drag force for the closed car De in terms of the speed U. the frontal area A, air density p, the drag coefficient CDc² (b) What is the expression for the power P. for the closed car? (c) What is the expression for the power P, for the open car? The speed is U. drag coefficient is Cp₂. (a) D. = ² x 2 (b) P = DV X (c) P. (AL) X Edit
(a) For the same power, what is the speed U, in terms of the variables of the problem? (b) What is the value of the speed for the open car if the closed car speed is 65 mph? (a) U=U U=Uc U=U, UU. 139.89 (b) O Cpe Cou CD 0% Com CD₂ mph
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!