- Tand Ktan Kr R Tank R K Ktan K R Tan Kr 1 B Calculate The Phase Shift 8 For 160 208 Pb Reaction At An Incident 1 (17.56 KiB) Viewed 60 times
- Tand Ktan Kr R Tank R K Ktan K R Tan Kr 1 B Calculate The Phase Shift 8 For 160 208 Pb Reaction At An Incident 2 (40.5 KiB) Viewed 60 times
tand ktan(KR) - R tank R) K+ktan(k:R) tan(KR) (1) (b) Calculate the phase shift 8 for 160+208 Pb reaction at an incident energy E = 20.0 MeV, consider U. = 102.0 MeV. (15) Question 4 Using the same equation (1), calculate the phase shift for a Helium atom scattered off a Sodium atom ("He + 23Na) at an incident energy E = 5.0 K (Kelvins). (20)
Question 3 Let us consider that the two particles interact via an attractive square well potential, i.e -Uo r≤R V(r) = -{{ 0 r> R, where R = 1.2 fm(A/3+ A/3), with A, and A₂, the particles' atomic masses. For the s-wave state (l=0), the above equation has the following form Csin(Kr) TSR uo(k,r)= sin(kr +80) r> R₁ (k+Uo), and do the scattering phase shift. Using where is a normalization constant, K² = the continuity of the wave function and its derivative at r= R, i.e d Csin(KR) = sin(kR +80), d dR Csin(KR)= = sin(kR+do), dR (a) show that the phase phift is given by (15) tan do= k tan(KR) - K tan(kR) K+ k tan(kR) tan(KR) (1) (b) Calculate the phase shift 6 for ¹60+208 Pb reaction at an incident energy E = 20.0 MeV, consider Uo = 102.0 MeV. (15) Question 4 Using the same equation (1), calculate the phase shift for a Helium atom scattered off a Sodium atom (He+23Na) at an incident energy E = 5.0 K (Kelvins). (20)