2. 185 points MATLAB Simulation: The continuous-time signal x(t) = 4sin(2t + 3mt) is sampled with T, = 0.01 s. Then the

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answerhappygod
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2. 185 points MATLAB Simulation: The continuous-time signal x(t) = 4sin(2t + 3mt) is sampled with T, = 0.01 s. Then the

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2 185 Points Matlab Simulation The Continuous Time Signal X T 4sin 2t 3mt Is Sampled With T 0 01 S Then The 1
2 185 Points Matlab Simulation The Continuous Time Signal X T 4sin 2t 3mt Is Sampled With T 0 01 S Then The 1 (21.5 KiB) Viewed 23 times
2. 185 points MATLAB Simulation: The continuous-time signal x(t) = 4sin(2t + 3mt) is sampled with T, = 0.01 s. Then the sampled signal is applied to the PCM system. In the PCM system. The n-bit uniform quantization method is utilized and the quantization levels are chosen in the middle of the quantization steps. a) Plot X(t), and sampled signal x,C) for the interval 0 st 52. b) Plot the quantization function with the range (-44] for n = 3. c) Plot the quantized signal xy(t). d) Plot quantization error (no(t) = x(t) - Xg(t)). e) Plot normalized histogram of the quantization error ) Write the encoded bits for the first 10 samples. B) Calculate the signal-to-quantization noise ratio. h) Repeat from (b) to (B) for n = 6.
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