Log 10 Reduction Value Credits Exhibit 10 1 Ct Values Mg Min L For Cryptosporidium Inactivation By Chlorine Dioxide Wa 1 (210.58 KiB) Viewed 21 times
Log 10 Reduction Value Credits Exhibit 10.1 CT Values (mg-min/L) for Cryptosporidium Inactivation by Chlorine Dioxide Water Temperature, C Log credit <=0.5 1 2 3 5 7 10 15 20 25 30 0.25 159 153 140 128 107 90 69 45 29 19 12 0.5 319 305 279 256 214 180 138 89 58 38 24 1.0 637 610 558 511 429 360 277 179 116 75 49 1.5 956 915 838 767 643 539 415 268 174 113 73 2.0 1275 1220 1117 1023 858 719 553 357 232 150 98 2.5 1594 1525 1396 1278 1072 899 691 447 289 188 122 3.0 1912 1830 1675 1534 1286 1079 830 536 347 226 147 "Systems may use this equation to determine log credit between the indicated values: Log credit (0.001506x(1.09116) Temp)x CT
3. At the Pure Water San Diego Advanced Water Purification Demonstration Facility, ultrafiltration membranes provided 2-log removal of viruses. A. If the overall removal of viruses needs to be 4-log, what UV dose is still required? Use the figure below showing the dose for log inactivation of the MS2 virus to determine the dose. 10 8 6 Log inactivation, -log(N/NO) 0 50 100 150 UV dose, mJ/cm2 Dose-response curve for bacteriophage MS2. The equation of the line, based on a linear fit, is y = 0.269 +0.04365x which corresponds to -log(N/N) = 0.269 + (0.04365 cm²/mJ) (UV dose, mJ/cm²) B. If the average intensity of one 254 nm UV lamp is 5 mW/cm2, then what is the contact time required for disinfection of viruses and cryptosporidium? (Note: mJ/cm2 = mW-s/cm2]
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