2) If the mid-cylinder moves out-of-phase by 90°, i.e. P:R (Right-Cylinder) = 5.0 X sin(2tt x 10) PzM(Mid-Cylinder) = 7.

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answerhappygod
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2) If the mid-cylinder moves out-of-phase by 90°, i.e. P:R (Right-Cylinder) = 5.0 X sin(2tt x 10) PzM(Mid-Cylinder) = 7.

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2 If The Mid Cylinder Moves Out Of Phase By 90 I E P R Right Cylinder 5 0 X Sin 2tt X 10 Pzm Mid Cylinder 7 1
2 If The Mid Cylinder Moves Out Of Phase By 90 I E P R Right Cylinder 5 0 X Sin 2tt X 10 Pzm Mid Cylinder 7 1 (33.8 KiB) Viewed 13 times
2) If the mid-cylinder moves out-of-phase by 90°, i.e. P:R (Right-Cylinder) = 5.0 X sin(2tt x 10) PzM(Mid-Cylinder) = 7.0X sin(2tx 10+ n/2) P: (lef-Cylinder) = 5.0 X sin(2t x 10), briefly describe how the effect of this phase difference can be taken into account. (Note: You do not need to redesign the foundation for this case.) Р. Р.м Рак Compressor (10 tonnes) Motor (1.5 tonnes) 1.2 m 1.2 m 3.0 m Figure 1
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