1 clc clear all 2 3 4 5 6 7 % Paramters for spring mass system m1 = 0.05; m2 = 2.5; W = 2*pi*1800/60; k = 1000; zeta = 0

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

1 clc clear all 2 3 4 5 6 7 % Paramters for spring mass system m1 = 0.05; m2 = 2.5; W = 2*pi*1800/60; k = 1000; zeta = 0

Post by answerhappygod »

1 Clc Clear All 2 3 4 5 6 7 Paramters For Spring Mass System M1 0 05 M2 2 5 W 2 Pi 1800 60 K 1000 Zeta 0 1
1 Clc Clear All 2 3 4 5 6 7 Paramters For Spring Mass System M1 0 05 M2 2 5 W 2 Pi 1800 60 K 1000 Zeta 0 1 (54.64 KiB) Viewed 42 times
what is 5*tau coming from?
what is the equation that reference from?
1 clc clear all 2 3 4 5 6 7 % Paramters for spring mass system m1 = 0.05; m2 = 2.5; W = 2*pi*1800/60; k = 1000; zeta = 0.5; e = 0.3; wn = 20; % Natural frequency 8 9 10 11 12 13 14 15 r = w/wn; % Frequency ratio FO = m1* (W^2)*e; MF = sqrt(((1 - 7^2)^2) + ((2*zeta*r)^2)); % Magnification factor %% Maximum Amplitude X = (F0/k)/ME 16 17 18 19 20 tau = 1/(zeta*wn); % time constant %% Time required to staedy state Tss = 5*tau 21
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply