temperature change.
b) Draw the bending moment (M) diagram due to ∆t = +15 ◦C
relative temperature change.
c) Draw the bending moment (M) diagram due to the prescribed
support settlements (EI = 1.800.000 kNm2 , ε = 10^(−5)
1/◦C). ε = 0,00001
- A Draw The Bending Moment M Diagram Due To T 20 C Uniform Temperature Change B Draw The Bending Moment M Diag 1 (54.13 KiB) Viewed 36 times
- A Draw The Bending Moment M Diagram Due To T 20 C Uniform Temperature Change B Draw The Bending Moment M Diag 2 (59.76 KiB) Viewed 36 times
- A Draw The Bending Moment M Diagram Due To T 20 C Uniform Temperature Change B Draw The Bending Moment M Diag 3 (60.2 KiB) Viewed 36 times
SM; Mx dx = 1 Value of the table --10-10- LILID Sait 1 (59) 0 2 0 0 ( + ) 1 +) (1 +) ) + (43+992 +975 (19+ 20192 | 18+12 ( (+) + (+24) 1 tetu+ ++ ) 1 1 0 ON - ) 1 1 6 0 1 12 ( 12) B 1 [ 1 1 7 uc 중에 예를 (+) 1 -1*(1 + $a- 12 jk 127 8 * 0 1 -10-pad 이지 () 0 () 1 12 **(1+28-) (--) ey 120 (4+1+ 10 SHIP Quadratic equation 0 15 - 이 11 0 0 1 12 11-23) Quadratic equation
SM; Mx dx = 1. Value of the table 를 al- cm 12 1 22 (5+3 重量 7 量 24 1 18 Quadratic equation 13 5 12 $(3+5) 12 ਨੇ 1 --- 12 8 15 Quadratic equation 24 6 *++) 1 1 14 Quadratic equation 1 12 (+32) 1 24 1 120++ a) 12 1 - 15 12 1 12 +( 3+ 5 18 24 1 120++) 12 Quadratic equation 1 10 Quadratic equation 12 * 520-80–2)) 12 0 FR[1-11-2011 8 Quadratic equation 1/2 18 +4+5+5+(35+ 1 128, +24,-4G 16 (2G7+ 4+ -10-25, +++ Quadratic equation 3 19 1 20 (+42 1 20 (a)(1+) 20 Cubic equation 3 20 * 1 *(4,+,) 20 금 1 2(1+(1+ 20 Cubic equation 30 20 40 1 21 8-31 -7171, +82) 00 1 12 00 1 20 Cubic equation 20 105 1 22 1 (8,7) 30 00 8 105 60 40 20 Cubic equation