The horizontal distance between the supports A and E of the cable shown in Figure 3 below is 60.0m with point E below po

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The Horizontal Distance Between The Supports A And E Of The Cable Shown In Figure 3 Below Is 60 0m With Point E Below Po 1 (52.75 KiB) Viewed 39 times

The horizontal distance between the supports A and E of the cable shown in Figure 3 below is 60.0m with point E below point A. At a horizontal distance of 15m, 30m, 45m measured from point A, concentrated loads of 200N, 400kN and 200kN were applied respectively. The suspended cable sags at point c equal to 15m. Using the principle of simple beam analogy, analyse and calculate the magnitude of the following: Part 1: The values of di, da, da, yı and ya: Part 2: The horizontal reactions at points A and E: Part 3: The maximum tensile force in cable ABCDE. Part4: The diameter of the suspended cable to carry the maximum tensile force using an allowable tensile stress of 500 MPa, f di d) iyi 24m E B !y2 = 15m Win 200KN 400KN 200KN 15.0m 15.Om 15.0m 15.0m 60.0m FIGURE 3