1. Given the following data for this reaction 2C102 +2 OH- -->C1031-+C102- + H20 EXPT [C102] (M) [OH) (M) RATE (M/s) 1 0

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answerhappygod
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1. Given the following data for this reaction 2C102 +2 OH- -->C1031-+C102- + H20 EXPT [C102] (M) [OH) (M) RATE (M/s) 1 0

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1 Given The Following Data For This Reaction 2c102 2 Oh C1031 C102 H20 Expt C102 M Oh M Rate M S 1 0 1
1 Given The Following Data For This Reaction 2c102 2 Oh C1031 C102 H20 Expt C102 M Oh M Rate M S 1 0 1 (60.9 KiB) Viewed 37 times
1. Given the following data for this reaction 2C102 +2 OH- -->C1031-+C102- + H20 EXPT [C102] (M) [OH) (M) RATE (M/s) 1 0.050 0.100 5.75 x 10-2 2 0.100 0.100 2.30x 10-1 3 0.100 0.050 1.15 x 10-1 The rate law for the reaction is: o O Rate = k1f10,7(OH), K = 157 O Rate = k[C102] [OH]", K = 355 Rate = k[C1021[OH], K = 230 Rate = k[C102° [OH], K-400
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