If 31.2 mL of lead(II) nitrate solution reacts completely with excess sodium lodide solution to yield 0.145 g of the pre

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If 31.2 mL of lead(II) nitrate solution reacts completely with excess sodium lodide solution to yield 0.145 g of the pre

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If 31 2 Ml Of Lead Ii Nitrate Solution Reacts Completely With Excess Sodium Lodide Solution To Yield 0 145 G Of The Pre 1
If 31 2 Ml Of Lead Ii Nitrate Solution Reacts Completely With Excess Sodium Lodide Solution To Yield 0 145 G Of The Pre 1 (10.19 KiB) Viewed 42 times
If 31.2 mL of lead(II) nitrate solution reacts completely with excess sodium lodide solution to yield 0.145 g of the precipitate lead(II) iodide, what is the molarity of lead(II)ion in the original solution?
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