- 5 For The Van De Pol Equation X2 1 R 0 The Parameter Is Positve What If I Were Negative For Example 1 What 1 (15.31 KiB) Viewed 21 times
5. For the Van de Pol equation, (x2 - 1)*+r=0 the parameter is positve. What if i were negative, for example = -1. What
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5. For the Van de Pol equation, (x2 - 1)*+r=0 the parameter is positve. What if i were negative, for example = -1. What
5. For the Van de Pol equation, (x2 - 1)*+r=0 the parameter is positve. What if i were negative, for example = -1. What do you expect would happen (brief description)? Use your intuition about 2nd order ODE and oscillators, classify the sole equilibrium point at (x,x) = (0,0), and sketch a phase-portrait for this equation with = -1 to support your answer. (Bonus: is ji = 0 a bifurcation value? Why or why not?)
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