New Case Another Sample Part E New Case To Have An Initial Activity Of Ro 11142 41 Bq Decays S What Is The Numb 1 (57.69 KiB) Viewed 42 times
New Case Another Sample Part E New Case To Have An Initial Activity Of Ro 11142 41 Bq Decays S What Is The Numb 2 (40.16 KiB) Viewed 42 times
New Case Another Sample Part E New Case To Have An Initial Activity Of Ro 11142 41 Bq Decays S What Is The Numb 3 (36.69 KiB) Viewed 42 times
New case: Another sample Part E - New case: To have an initial activity of Ro = 11142.41 Bq (decays/s), what is the number of radioactive nuclei in the initial sample? Use scientific notations, 1.234'10" No = 9.00x1010 Submit Previous Answers ✓ Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. v Part F- New case: After 7.50 days what is the activity in decays/s (Ba)? Keep 2 digits after the decimal point. Вq R = 10283.43 Previous Answers
Part G - New case: same sample as in Part E and F. How many days does it take for the activity to reach 9490.66 Bq ? VO ΑΣΦ ? tnew = 300.9 days Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
A radioactive sample's half-life is 64.8 days. 1 day = 24 hours, 1 hour = 60 min, 1 min = 60 s Part A What is the decay constant in day? Keep 4 digits after the decimal point. 1 = 1.07x10-2 day! - 1 Subm Previous Answers 2.1 Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations Part B What is the decay constant ins? Use scientific notations, format 1.234'10". 87 X = 1.238x10-7
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