3. Question 3 [13] Figure 3.1(a) illustrates a system with a mass of m= 20 kg, damping coefficient of c = 120 N s/m, spr

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3. Question 3 [13] Figure 3.1(a) illustrates a system with a mass of m= 20 kg, damping coefficient of c = 120 N s/m, spr

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3 Question 3 13 Figure 3 1 A Illustrates A System With A Mass Of M 20 Kg Damping Coefficient Of C 120 N S M Spr 1
3 Question 3 13 Figure 3 1 A Illustrates A System With A Mass Of M 20 Kg Damping Coefficient Of C 120 N S M Spr 1 (70.1 KiB) Viewed 22 times
3 Question 3 13 Figure 3 1 A Illustrates A System With A Mass Of M 20 Kg Damping Coefficient Of C 120 N S M Spr 2
3 Question 3 13 Figure 3 1 A Illustrates A System With A Mass Of M 20 Kg Damping Coefficient Of C 120 N S M Spr 2 (65.4 KiB) Viewed 22 times
3. Question 3 [13] Figure 3.1(a) illustrates a system with a mass of m= 20 kg, damping coefficient of c = 120 N s/m, springs stiffnesses of kı = 4800N/m, kz = 400N/m, and kz = 800N/m attached to the mass placed on frictionless rollers. The system is constructed in Wolfram System Modeller as shown in Figure 3.1 (b). If the mass is given a small displacement and then released, the results displayed in Figure 3.2 show that the system is underdamped. 3.1. The natural frequency. [4] 3.2. The Damping ratio. [3] 3.3. Compute the solution for the plot, by computing the constants C and C and expressing your equation in its simplest form, if the initial displacement is xy = 0.2 m, and initial velocity *, - 0 m/s [6] , df
3.3. Compute the solution for the plot, by computing the constants C and C2 and expressing your equation in its simplest form, if the initial displacement is x, = 0.2 m, and initial velocity *, = 0 m/s. [6] 120 Nm mass 1 spring 0 Nm 200 m WW w M DITORIO WOON SHOW (a) (b) Figure 3.1 Spring mass damper system of
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